2=-16x^2+64x+80

Solution for 2=-16x^2+64x+80 equation:

2=-16x^2+64x+80

We move all terms to the left:

2-(-16x^2+64x+80)=0

We get rid of parentheses

16x^2-64x-80+2=0

We add all the numbers together, and all the variables

16x^2-64x-78=0

a = 16; b = -64; c = -78;
Δ = b2-4ac
Δ = -642-4·16·(-78)
Δ = 9088
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9088}=\sqrt{64*142}=\sqrt{64}*\sqrt{142}=8\sqrt{142}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-8\sqrt{142}}{2*16}=\frac{64-8\sqrt{142}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+8\sqrt{142}}{2*16}=\frac{64+8\sqrt{142}}{32}
$